Integrand size = 29, antiderivative size = 178 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {(e f+d g)^2}{32 d^5 e^3 (d-e x)}-\frac {(e f-d g)^2}{16 d^2 e^3 (d+e x)^4}-\frac {e^2 f^2-d^2 g^2}{12 d^3 e^3 (d+e x)^3}-\frac {(3 e f-d g) (e f+d g)}{32 d^4 e^3 (d+e x)^2}-\frac {f (e f+d g)}{8 d^5 e^2 (d+e x)}+\frac {(e f+d g) (5 e f+d g) \text {arctanh}\left (\frac {e x}{d}\right )}{32 d^6 e^3} \]
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Time = 0.13 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {862, 90, 214} \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {\text {arctanh}\left (\frac {e x}{d}\right ) (d g+e f) (d g+5 e f)}{32 d^6 e^3}+\frac {(d g+e f)^2}{32 d^5 e^3 (d-e x)}-\frac {f (d g+e f)}{8 d^5 e^2 (d+e x)}-\frac {(3 e f-d g) (d g+e f)}{32 d^4 e^3 (d+e x)^2}-\frac {(e f-d g)^2}{16 d^2 e^3 (d+e x)^4}-\frac {e^2 f^2-d^2 g^2}{12 d^3 e^3 (d+e x)^3} \]
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Rule 90
Rule 214
Rule 862
Rubi steps \begin{align*} \text {integral}& = \int \frac {(f+g x)^2}{(d-e x)^2 (d+e x)^5} \, dx \\ & = \int \left (\frac {(e f+d g)^2}{32 d^5 e^2 (d-e x)^2}+\frac {(-e f+d g)^2}{4 d^2 e^2 (d+e x)^5}+\frac {e^2 f^2-d^2 g^2}{4 d^3 e^2 (d+e x)^4}+\frac {(3 e f-d g) (e f+d g)}{16 d^4 e^2 (d+e x)^3}+\frac {f (e f+d g)}{8 d^5 e (d+e x)^2}+\frac {(e f+d g) (5 e f+d g)}{32 d^5 e^2 \left (d^2-e^2 x^2\right )}\right ) \, dx \\ & = \frac {(e f+d g)^2}{32 d^5 e^3 (d-e x)}-\frac {(e f-d g)^2}{16 d^2 e^3 (d+e x)^4}-\frac {e^2 f^2-d^2 g^2}{12 d^3 e^3 (d+e x)^3}-\frac {(3 e f-d g) (e f+d g)}{32 d^4 e^3 (d+e x)^2}-\frac {f (e f+d g)}{8 d^5 e^2 (d+e x)}+\frac {((e f+d g) (5 e f+d g)) \int \frac {1}{d^2-e^2 x^2} \, dx}{32 d^5 e^2} \\ & = \frac {(e f+d g)^2}{32 d^5 e^3 (d-e x)}-\frac {(e f-d g)^2}{16 d^2 e^3 (d+e x)^4}-\frac {e^2 f^2-d^2 g^2}{12 d^3 e^3 (d+e x)^3}-\frac {(3 e f-d g) (e f+d g)}{32 d^4 e^3 (d+e x)^2}-\frac {f (e f+d g)}{8 d^5 e^2 (d+e x)}+\frac {(e f+d g) (5 e f+d g) \tanh ^{-1}\left (\frac {e x}{d}\right )}{32 d^6 e^3} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 195, normalized size of antiderivative = 1.10 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {\frac {6 d (e f+d g)^2}{d-e x}-\frac {12 d^4 (e f-d g)^2}{(d+e x)^4}+\frac {16 d^3 \left (-e^2 f^2+d^2 g^2\right )}{(d+e x)^3}+\frac {6 d^2 \left (-3 e^2 f^2-2 d e f g+d^2 g^2\right )}{(d+e x)^2}-\frac {24 d e f (e f+d g)}{d+e x}-3 \left (5 e^2 f^2+6 d e f g+d^2 g^2\right ) \log (d-e x)+3 \left (5 e^2 f^2+6 d e f g+d^2 g^2\right ) \log (d+e x)}{192 d^6 e^3} \]
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Time = 0.42 (sec) , antiderivative size = 241, normalized size of antiderivative = 1.35
method | result | size |
default | \(\frac {\left (-d^{2} g^{2}-6 d e f g -5 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{64 e^{3} d^{6}}+\frac {d^{2} g^{2}+2 d e f g +e^{2} f^{2}}{32 e^{3} d^{5} \left (-e x +d \right )}+\frac {\left (d^{2} g^{2}+6 d e f g +5 e^{2} f^{2}\right ) \ln \left (e x +d \right )}{64 e^{3} d^{6}}-\frac {-d^{2} g^{2}+e^{2} f^{2}}{12 e^{3} d^{3} \left (e x +d \right )^{3}}-\frac {-d^{2} g^{2}+2 d e f g +3 e^{2} f^{2}}{32 e^{3} d^{4} \left (e x +d \right )^{2}}-\frac {d^{2} g^{2}-2 d e f g +e^{2} f^{2}}{16 d^{2} e^{3} \left (e x +d \right )^{4}}-\frac {f \left (d g +e f \right )}{8 d^{5} e^{2} \left (e x +d \right )}\) | \(241\) |
norman | \(\frac {\frac {\left (25 d^{2} g^{2}+54 d e f g -19 e^{2} f^{2}\right ) x^{3}}{96 d^{4}}-\frac {\left (3 d^{2} g^{2}-14 d e f g -33 e^{2} f^{2}\right ) x^{2}}{32 e \,d^{3}}+\frac {3 e \left (3 d^{2} g^{2}+2 d e f g -9 e^{2} f^{2}\right ) x^{4}}{32 d^{5}}+\frac {e^{2} \left (d^{2} g^{2}-4 e^{2} f^{2}\right ) x^{5}}{12 d^{6}}-\frac {\left (d^{2} g^{2}+6 d e f g -27 e^{2} f^{2}\right ) x}{32 d^{2} e^{2}}}{\left (e x +d \right )^{4} \left (-e x +d \right )}-\frac {\left (d^{2} g^{2}+6 d e f g +5 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{64 e^{3} d^{6}}+\frac {\left (d^{2} g^{2}+6 d e f g +5 e^{2} f^{2}\right ) \ln \left (e x +d \right )}{64 e^{3} d^{6}}\) | \(247\) |
risch | \(\frac {\frac {e \left (d^{2} g^{2}+6 d e f g +5 e^{2} f^{2}\right ) x^{4}}{32 d^{5}}+\frac {3 \left (d^{2} g^{2}+6 d e f g +5 e^{2} f^{2}\right ) x^{3}}{32 d^{4}}+\frac {7 \left (d^{2} g^{2}+6 d e f g +5 e^{2} f^{2}\right ) x^{2}}{96 d^{3} e}+\frac {\left (7 d^{2} g^{2}-6 d e f g -5 e^{2} f^{2}\right ) x}{32 d^{2} e^{2}}+\frac {d^{2} g^{2}-4 e^{2} f^{2}}{12 d \,e^{3}}}{\left (e x +d \right )^{3} \left (-e^{2} x^{2}+d^{2}\right )}-\frac {\ln \left (-e x +d \right ) g^{2}}{64 e^{3} d^{4}}-\frac {3 \ln \left (-e x +d \right ) f g}{32 e^{2} d^{5}}-\frac {5 \ln \left (-e x +d \right ) f^{2}}{64 e \,d^{6}}+\frac {\ln \left (e x +d \right ) g^{2}}{64 e^{3} d^{4}}+\frac {3 \ln \left (e x +d \right ) f g}{32 e^{2} d^{5}}+\frac {5 \ln \left (e x +d \right ) f^{2}}{64 e \,d^{6}}\) | \(278\) |
parallelrisch | \(-\frac {-15 \ln \left (e x +d \right ) x^{5} e^{7} f^{2}+15 \ln \left (e x -d \right ) x^{5} e^{7} f^{2}+162 x \,d^{4} e^{3} f^{2}+54 \ln \left (e x +d \right ) x \,d^{5} e^{2} f g +3 \ln \left (e x -d \right ) x^{5} d^{2} e^{5} g^{2}-3 \ln \left (e x +d \right ) x^{5} d^{2} e^{5} g^{2}+9 \ln \left (e x -d \right ) x^{4} d^{3} e^{4} g^{2}+45 \ln \left (e x -d \right ) x^{4} d \,e^{6} f^{2}-9 \ln \left (e x +d \right ) x^{4} d^{3} e^{4} g^{2}-45 \ln \left (e x +d \right ) x^{4} d \,e^{6} f^{2}+6 \ln \left (e x -d \right ) x^{3} d^{4} e^{3} g^{2}+30 \ln \left (e x -d \right ) x^{3} d^{2} e^{5} f^{2}-9 \ln \left (e x -d \right ) x \,d^{6} e \,g^{2}-45 \ln \left (e x -d \right ) x \,d^{4} e^{3} f^{2}-18 \ln \left (e x -d \right ) d^{6} e f g -6 x \,d^{6} e \,g^{2}+198 x^{2} d^{3} e^{4} f^{2}+50 x^{3} d^{4} e^{3} g^{2}-38 x^{3} d^{2} e^{5} f^{2}+54 x^{4} d^{3} e^{4} g^{2}-162 x^{4} d \,e^{6} f^{2}+16 x^{5} d^{2} e^{5} g^{2}-15 \ln \left (e x -d \right ) d^{5} e^{2} f^{2}-18 x^{2} d^{5} e^{2} g^{2}-54 \ln \left (e x -d \right ) x \,d^{5} e^{2} f g +15 \ln \left (e x +d \right ) d^{5} e^{2} f^{2}-6 \ln \left (e x +d \right ) x^{3} d^{4} e^{3} g^{2}-30 \ln \left (e x +d \right ) x^{3} d^{2} e^{5} f^{2}-6 \ln \left (e x -d \right ) x^{2} d^{5} e^{2} g^{2}-30 \ln \left (e x -d \right ) x^{2} d^{3} e^{4} f^{2}+6 \ln \left (e x +d \right ) x^{2} d^{5} e^{2} g^{2}+30 \ln \left (e x +d \right ) x^{2} d^{3} e^{4} f^{2}+9 \ln \left (e x +d \right ) x \,d^{6} e \,g^{2}+45 \ln \left (e x +d \right ) x \,d^{4} e^{3} f^{2}+18 \ln \left (e x +d \right ) d^{6} e f g -36 x \,d^{5} e^{2} f g -3 \ln \left (e x -d \right ) d^{7} g^{2}+18 \ln \left (e x -d \right ) x^{5} d \,e^{6} f g -18 \ln \left (e x +d \right ) x^{5} d \,e^{6} f g -64 x^{5} e^{7} f^{2}+3 \ln \left (e x +d \right ) d^{7} g^{2}+84 x^{2} d^{4} e^{3} f g +108 x^{3} d^{3} e^{4} f g +36 x^{4} d^{2} e^{5} f g +54 \ln \left (e x -d \right ) x^{4} d^{2} e^{5} f g -54 \ln \left (e x +d \right ) x^{4} d^{2} e^{5} f g +36 \ln \left (e x -d \right ) x^{3} d^{3} e^{4} f g -36 \ln \left (e x +d \right ) x^{3} d^{3} e^{4} f g -36 \ln \left (e x -d \right ) x^{2} d^{4} e^{3} f g +36 \ln \left (e x +d \right ) x^{2} d^{4} e^{3} f g}{192 e^{3} d^{6} \left (e^{2} x^{2}-d^{2}\right ) \left (e x +d \right )^{3}}\) | \(897\) |
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Leaf count of result is larger than twice the leaf count of optimal. 648 vs. \(2 (167) = 334\).
Time = 0.35 (sec) , antiderivative size = 648, normalized size of antiderivative = 3.64 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {64 \, d^{5} e^{2} f^{2} - 16 \, d^{7} g^{2} - 6 \, {\left (5 \, d e^{6} f^{2} + 6 \, d^{2} e^{5} f g + d^{3} e^{4} g^{2}\right )} x^{4} - 18 \, {\left (5 \, d^{2} e^{5} f^{2} + 6 \, d^{3} e^{4} f g + d^{4} e^{3} g^{2}\right )} x^{3} - 14 \, {\left (5 \, d^{3} e^{4} f^{2} + 6 \, d^{4} e^{3} f g + d^{5} e^{2} g^{2}\right )} x^{2} + 6 \, {\left (5 \, d^{4} e^{3} f^{2} + 6 \, d^{5} e^{2} f g - 7 \, d^{6} e g^{2}\right )} x - 3 \, {\left (5 \, d^{5} e^{2} f^{2} + 6 \, d^{6} e f g + d^{7} g^{2} - {\left (5 \, e^{7} f^{2} + 6 \, d e^{6} f g + d^{2} e^{5} g^{2}\right )} x^{5} - 3 \, {\left (5 \, d e^{6} f^{2} + 6 \, d^{2} e^{5} f g + d^{3} e^{4} g^{2}\right )} x^{4} - 2 \, {\left (5 \, d^{2} e^{5} f^{2} + 6 \, d^{3} e^{4} f g + d^{4} e^{3} g^{2}\right )} x^{3} + 2 \, {\left (5 \, d^{3} e^{4} f^{2} + 6 \, d^{4} e^{3} f g + d^{5} e^{2} g^{2}\right )} x^{2} + 3 \, {\left (5 \, d^{4} e^{3} f^{2} + 6 \, d^{5} e^{2} f g + d^{6} e g^{2}\right )} x\right )} \log \left (e x + d\right ) + 3 \, {\left (5 \, d^{5} e^{2} f^{2} + 6 \, d^{6} e f g + d^{7} g^{2} - {\left (5 \, e^{7} f^{2} + 6 \, d e^{6} f g + d^{2} e^{5} g^{2}\right )} x^{5} - 3 \, {\left (5 \, d e^{6} f^{2} + 6 \, d^{2} e^{5} f g + d^{3} e^{4} g^{2}\right )} x^{4} - 2 \, {\left (5 \, d^{2} e^{5} f^{2} + 6 \, d^{3} e^{4} f g + d^{4} e^{3} g^{2}\right )} x^{3} + 2 \, {\left (5 \, d^{3} e^{4} f^{2} + 6 \, d^{4} e^{3} f g + d^{5} e^{2} g^{2}\right )} x^{2} + 3 \, {\left (5 \, d^{4} e^{3} f^{2} + 6 \, d^{5} e^{2} f g + d^{6} e g^{2}\right )} x\right )} \log \left (e x - d\right )}{192 \, {\left (d^{6} e^{8} x^{5} + 3 \, d^{7} e^{7} x^{4} + 2 \, d^{8} e^{6} x^{3} - 2 \, d^{9} e^{5} x^{2} - 3 \, d^{10} e^{4} x - d^{11} e^{3}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 376 vs. \(2 (162) = 324\).
Time = 0.80 (sec) , antiderivative size = 376, normalized size of antiderivative = 2.11 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {- 8 d^{6} g^{2} + 32 d^{4} e^{2} f^{2} + x^{4} \left (- 3 d^{2} e^{4} g^{2} - 18 d e^{5} f g - 15 e^{6} f^{2}\right ) + x^{3} \left (- 9 d^{3} e^{3} g^{2} - 54 d^{2} e^{4} f g - 45 d e^{5} f^{2}\right ) + x^{2} \left (- 7 d^{4} e^{2} g^{2} - 42 d^{3} e^{3} f g - 35 d^{2} e^{4} f^{2}\right ) + x \left (- 21 d^{5} e g^{2} + 18 d^{4} e^{2} f g + 15 d^{3} e^{3} f^{2}\right )}{- 96 d^{10} e^{3} - 288 d^{9} e^{4} x - 192 d^{8} e^{5} x^{2} + 192 d^{7} e^{6} x^{3} + 288 d^{6} e^{7} x^{4} + 96 d^{5} e^{8} x^{5}} - \frac {\left (d g + e f\right ) \left (d g + 5 e f\right ) \log {\left (- \frac {d \left (d g + e f\right ) \left (d g + 5 e f\right )}{e \left (d^{2} g^{2} + 6 d e f g + 5 e^{2} f^{2}\right )} + x \right )}}{64 d^{6} e^{3}} + \frac {\left (d g + e f\right ) \left (d g + 5 e f\right ) \log {\left (\frac {d \left (d g + e f\right ) \left (d g + 5 e f\right )}{e \left (d^{2} g^{2} + 6 d e f g + 5 e^{2} f^{2}\right )} + x \right )}}{64 d^{6} e^{3}} \]
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Time = 0.20 (sec) , antiderivative size = 298, normalized size of antiderivative = 1.67 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {32 \, d^{4} e^{2} f^{2} - 8 \, d^{6} g^{2} - 3 \, {\left (5 \, e^{6} f^{2} + 6 \, d e^{5} f g + d^{2} e^{4} g^{2}\right )} x^{4} - 9 \, {\left (5 \, d e^{5} f^{2} + 6 \, d^{2} e^{4} f g + d^{3} e^{3} g^{2}\right )} x^{3} - 7 \, {\left (5 \, d^{2} e^{4} f^{2} + 6 \, d^{3} e^{3} f g + d^{4} e^{2} g^{2}\right )} x^{2} + 3 \, {\left (5 \, d^{3} e^{3} f^{2} + 6 \, d^{4} e^{2} f g - 7 \, d^{5} e g^{2}\right )} x}{96 \, {\left (d^{5} e^{8} x^{5} + 3 \, d^{6} e^{7} x^{4} + 2 \, d^{7} e^{6} x^{3} - 2 \, d^{8} e^{5} x^{2} - 3 \, d^{9} e^{4} x - d^{10} e^{3}\right )}} + \frac {{\left (5 \, e^{2} f^{2} + 6 \, d e f g + d^{2} g^{2}\right )} \log \left (e x + d\right )}{64 \, d^{6} e^{3}} - \frac {{\left (5 \, e^{2} f^{2} + 6 \, d e f g + d^{2} g^{2}\right )} \log \left (e x - d\right )}{64 \, d^{6} e^{3}} \]
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Time = 0.28 (sec) , antiderivative size = 264, normalized size of antiderivative = 1.48 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {{\left (5 \, e^{2} f^{2} + 6 \, d e f g + d^{2} g^{2}\right )} \log \left ({\left | e x + d \right |}\right )}{64 \, d^{6} e^{3}} - \frac {{\left (5 \, e^{2} f^{2} + 6 \, d e f g + d^{2} g^{2}\right )} \log \left ({\left | e x - d \right |}\right )}{64 \, d^{6} e^{3}} + \frac {32 \, d^{5} e^{2} f^{2} - 8 \, d^{7} g^{2} - 3 \, {\left (5 \, d e^{6} f^{2} + 6 \, d^{2} e^{5} f g + d^{3} e^{4} g^{2}\right )} x^{4} - 9 \, {\left (5 \, d^{2} e^{5} f^{2} + 6 \, d^{3} e^{4} f g + d^{4} e^{3} g^{2}\right )} x^{3} - 7 \, {\left (5 \, d^{3} e^{4} f^{2} + 6 \, d^{4} e^{3} f g + d^{5} e^{2} g^{2}\right )} x^{2} + 3 \, {\left (5 \, d^{4} e^{3} f^{2} + 6 \, d^{5} e^{2} f g - 7 \, d^{6} e g^{2}\right )} x}{96 \, {\left (e x + d\right )}^{4} {\left (e x - d\right )} d^{6} e^{3}} \]
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Time = 11.80 (sec) , antiderivative size = 274, normalized size of antiderivative = 1.54 \[ \int \frac {(f+g x)^2}{(d+e x)^3 \left (d^2-e^2 x^2\right )^2} \, dx=\frac {\frac {d^2\,g^2-4\,e^2\,f^2}{12\,d\,e^3}+\frac {3\,x^3\,\left (d^2\,g^2+6\,d\,e\,f\,g+5\,e^2\,f^2\right )}{32\,d^4}+\frac {e\,x^4\,\left (d^2\,g^2+6\,d\,e\,f\,g+5\,e^2\,f^2\right )}{32\,d^5}-\frac {x\,\left (-7\,d^2\,g^2+6\,d\,e\,f\,g+5\,e^2\,f^2\right )}{32\,d^2\,e^2}+\frac {7\,x^2\,\left (d^2\,g^2+6\,d\,e\,f\,g+5\,e^2\,f^2\right )}{96\,d^3\,e}}{d^5+3\,d^4\,e\,x+2\,d^3\,e^2\,x^2-2\,d^2\,e^3\,x^3-3\,d\,e^4\,x^4-e^5\,x^5}+\frac {\mathrm {atanh}\left (\frac {e\,x\,\left (d\,g+e\,f\right )\,\left (d\,g+5\,e\,f\right )}{d\,\left (d^2\,g^2+6\,d\,e\,f\,g+5\,e^2\,f^2\right )}\right )\,\left (d\,g+e\,f\right )\,\left (d\,g+5\,e\,f\right )}{32\,d^6\,e^3} \]
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